The crane evenly lifts a load weighing 1.5 tons at a speed of 10 m / min.

univerkov | September 17, 2021 | education

The crane evenly lifts a load weighing 1.5 tons at a speed of 10 m / min. Determine the current strength in the crane motor, if the voltage at its terminals is 380V, and the efficiency of the crane is 80%.

Given: m (mass of the lifted load) = 1.5 t (in SI m = 1.5 * 10 ^ 3 kg); V (lifting speed) = 10 m / min (in SI V = 1/6 m / s); U (voltage at the motor terminals) = 380 V; η (crane efficiency) = 80% (0.8).

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

To determine the current in the crane motor, we use the formula: η = Ap / Az = m * g * h / (U * I * t) and I = m * g * h / (η * U * t) = m * g * V / (η * U).

Calculation: I = 1.5 * 10 ^ 3 * 10 * 1/6 / (0.8 * 380) = 8.22 A.

Answer: The current in the crane motor is 8.22 A.

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