The crane lifted a steel billet weighing 1.5 tons to a certain height in a time of 5 s.
| July 15, 2021 | education
The crane lifted a steel billet weighing 1.5 tons to a certain height in a time of 5 s. Determine the useful work done by the crane if the lifting speed was 20m / min.
Given: m (mass of the raised workpiece) = 1.5 t (in SI m = 1.5 * 10 ^ 3 kg); t (time spent by the crane) = 5 s; V (the speed of lifting the workpiece, for the calculation we will consider it constant) = 20 m / min (in SI V = 1/3 m / s).
Constants: g (acceleration due to gravity) ≈ 10 m / s2.
The useful work of the crane used when lifting the workpiece is calculated by the formula: A = N * t = F * V * t = m * g * V * t.
Calculation: A = 1.5 * 10 ^ 3 * 10 * 1/3 * 5 = 25 * 10 ^ 3 J (25 kJ).
Answer: The crane used did a useful job of 25 kJ.
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