The crane lifts a load weighing 12000 kg vertically upwards to a height of 5 m in 50 seconds.

The crane lifts a load weighing 12000 kg vertically upwards to a height of 5 m in 50 seconds. What mechanical power does it develop during this rise?

Initial data: t (duration of the crane operation) = 50 s; h (height to which the crane lifted the load) = 5 m; m (mass of the vertically lifted load) = 12000 kg.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

The mechanical power developed by the crane is determined by the formula: N = A / t = ΔEp / t = m * g * h / t.

Let’s make the calculation: N = 12000 * 10 * 5/50 = 12000 W (12 kW).

Answer: During the lifting of the load, the crane developed a power of 12 kW.