The crane lifts a load weighing 2 tons to a height of 5 m. What kind of work does it do?

The work that a given crane was supposed to perform can be represented in the form of the formula: A = F * S * cosα, where for vertical lifting cosα = 1. Therefore, A = F * S = m * g * h, where m is the mass lifted load (m = 2 t or 2 * 10 ^ 3 kg); g – acceleration due to gravity (g ≈ 10 m / s2); h – lifting height (h = 5 m).

Let’s calculate: A = m * g * h = 2 * 10 ^ 3 * 10 * 5 = 100 * 10 ^ 3 J or 100 kJ.

Answer: When lifting a load weighing 2 tons by a crane, a work of 100 kJ was performed.