The crane lifts a load weighing 200 kg from the ground within 10 seconds

The crane lifts a load weighing 200 kg from the ground within 10 seconds with an acceleration of 0.1 m / s. Determine the work to be done when lifting the load.

These tasks: t (duration of lifting the load by the crane) = 10 s; m (cargo weight) = 200 kg; a (acceleration of the load during lifting) = 0.1 m / s2.

Constants: g (acceleration due to gravity) ≈ 9.8 m / s2.

We calculate the work of the crane used by the formula: A = F * S = P * h = (m * (g + a)) * (a * t ^ 2/2).

Let’s calculate: A = 200 * (9.8 + 0.1) * 0.1 * 10 ^ 2/2 = 9900 J = 9.9 kJ.

Answer: When lifting the load, the crane used performed a work of 9.9 kJ.