The crane lifts a weight of 10kN vertically upwards to a height of 5m in 50 seconds. How much power

The crane lifts a weight of 10kN vertically upwards to a height of 5m in 50 seconds. How much power does he develop during this climb?

Given: t (duration of crane operation) = 50 s; h (lifting height) = 5 m; P (weight) = 10 kN (10 * 10 ^ 3 N).

The power that the crane used was supposed to develop is calculated by the formula: N = A / t = F * S / t = P * h / t.

Let’s make a calculation: N = 10 * 10 ^ 3 * 5/50 = 1 * 10 ^ 3 W (1 kW).

Answer: During the lifting of the load, the crane used developed a power of 1 kW.