The crane lifts the load at a speed of 0.5 m / s. What is the weight of the load if the crane performs
| August 2, 2021 | education
The crane lifts the load at a speed of 0.5 m / s. What is the weight of the load if the crane performs work of 1.2 MJ in 1 minute.
Given: V (the speed of lifting the load, the lifting will be considered uniform) = 0.5 m / s; t (lifting duration) = 1 min (in SI t = 60 s); A (work done by the crane) = 1.2 MJ (1.2 * 10 ^ 6 J).
Constants: g (acceleration due to gravity) ≈ 10 m / s2.
To determine the desired mass of the lifted load, we use the formula: A = ΔEp = m * g * h = m * g * V * t and m = A / (g * V * t).
Calculation: m = 1.2 * 10 ^ 6 / (10 * 0.5 * 60) = 4 * 10 ^ 3 kg (4 t).
Answer: The required mass of the lifted load is 4 tons.
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