The crane lifts the load evenly at a speed of 2m / s, while its engine developed a power

The crane lifts the load evenly at a speed of 2m / s, while its engine developed a power of 8kW. What is the weight of the load being lifted?

Given: V (speed of uniform lifting of the load) = 2 m / s; N (the power that the motor of the crane used was able to develop) = 8 kW (8000 W).

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

Since the load was lifted evenly, to calculate its mass, you can use the formula: N = F * V = m * g * V, whence m = N / (g * V).

Let’s calculate: m = 8000 / (10 * 2) = 400 kg.

Answer: V. The mass of the load being lifted is 400 kg.