The crane lifts the vehicle. What is the minimum work performed by a crane when a vehicle

The crane lifts the vehicle. What is the minimum work performed by a crane when a vehicle weighing 2000 kg is evenly lifted to a height of 12 m?

The given tasks: m (mass of the evenly lifted vehicle) = 2000 kg; h (lifting height) = 12 m.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

To determine the minimum work performed by the crane used, we use the formula: A = ΔEp = m * g * h.

Calculation: A = 2000 * 10 * 12 = 240 * 10 ^ 3 J = 240 kJ.

Answer: With uniform lifting of the vehicle, the minimum work of the crane should have been 240 kJ.



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