The crane lowers the load vertically downward at a certain speed V. When the load is at a height of H = 24 m, the crane cable

| November 19, 2020 | education

The crane lowers the load vertically downward at a certain speed V. When the load is at a height of H = 24 m, the crane cable breaks and the load falls down. If the time of the load falling to the ground is t = 2c, then the speed V is?

Distance traveled when falling:
S = V * t + a * t² / 2, where S is the height of the fall of the load (S = H = 24 m), V is the speed of lowering the load until the cable breaks (m / s), t is the time of the fall of the load (t = 2 s), a is the acceleration with which the load falls (a = g = 10 m / s²).
Let us express and calculate the speed of lowering the load until the cable breaks:
V * t = S – a * t² / 2.
V = (S – g * t² / 2) / t = (24 – 10 * 2² / 2) / 2 = (24 – 20) / 2 = 4/2 = 2 m / s.
Answer: The speed of lowering the load until the cable was broken was 2 m / s.



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