The current in a 40 m long nickel conductor is 0.5 A. Determine the cross-sectional

The current in a 40 m long nickel conductor is 0.5 A. Determine the cross-sectional area of the conductor if a voltage of 84 V is applied to its ends.

To calculate the required cross-sectional area of a given nickelin conductor, we use the equality: U / I = R = ρ * l / S and S = ρ * l * I / U.

Constants and variables: ρ is the specific electrical resistance of nickelin (ρ = 0.4 Ohm * mm2 / m); l – conductor length (l = 40 m); I – current strength (I = 0.5 A); U is the applied voltage (U = 84 V).

Calculation: S = ρ * l * I / U = 0.4 * 40 * 0.5 / 84 = 0.095 mm2.

Answer: The cross-sectional area of a given nickeline conductor is 0.095 mm2.