The current in a coil with an inductance of 3 H decreases uniformly in 0.1 s from 4A to 0A. What is the EMF of self-induction in this case?

E = L * I / t – EMF of self-induction. The topic is found in electrostatics and electrodynamics.
E = L * I / t = 3 * 4 / 0.1 = 1.2 V.
We write down the answer: E = 1.2 V.



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