The current in a conductor made of manganin is 0.5 A with a voltage at its ends of 6 V. What is the length
| July 24, 2021 | education
The current in a conductor made of manganin is 0.5 A with a voltage at its ends of 6 V. What is the length of the wire if its cross-sectional area is 0.25 mm2?
Solution:
R = U / I = 6 / 0.5 = 12 Ohm
R = pl / S = 12 0m
I = RS / p = 12 * 0.25: 0.43 = 3: 0.43 = 6.98 m
Answer: 6.98 m
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
