The current in a conductor made of manganin is 0.5 A with a voltage at its ends of 6 V. What is the length
July 24, 2021
The current in a conductor made of manganin is 0.5 A with a voltage at its ends of 6 V. What is the length of the wire if its cross-sectional area is 0.25 mm2?
R = U / I = 6 / 0.5 = 12 Ohm
R = pl / S = 12 0m
I = RS / p = 12 * 0.25: 0.43 = 3: 0.43 = 6.98 m
Answer: 6.98 m
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