The current in a conductor with a length of 1.5 m and a cross-sectional area of 0.02 mm (squared) is 0.25 A.

The current in a conductor with a length of 1.5 m and a cross-sectional area of 0.02 mm (squared) is 0.25 A. Determine the voltage at the ends of the conductor. Resistivity = 0.1 Ohm * mm2 / m.

Initial data: l (current in the conductor) = 1.5 m; S (cross-sectional area) = 0.02 mm2; I (current in the conductor) = 0.25 A; ρ (specific resistance of the conductor material) = 0.1 Ohm * mm2 / m.
The voltage at the ends of the conductor in question is determined from the equality: U / I = R = ρ * l / S, whence U = ρ * l * I / S.
Calculation: U = 0.1 * 1.5 * 0.25 / 0.02 = 1.875 V.
Answer: The voltage at the ends of the conductor in question is 1.875 V.