The current in a flashlight bulb is 0.5 A. What charge passes through the cross-section of the bulb’s filament in 1 hour?

Given:

I = 0.5 Ampere – the strength of the electric current in a flashlight bulb;

t = 1 hour – period of time.

It is required to determine q (Coulomb) – what charge passes through the cross-section of the light bulb filament in a time interval equal to t.

Let’s convert the units of measurement of time to the SI system:

t = 1 hour = 1 * 60 = 60 minutes = 60 * 60 = 3600 seconds.

Then, to determine the charge, you must use the following formula:

q = I * t = 0.5 * 3600 = 5 * 360 = 1800 Pendant.

Answer: in one hour, a charge equal to 1800 Coulomb (1.8 kK) passes through the cross section of the filament of the light bulb.