The current in the circuit was doubled, and its resistance was halved. Has the circuit changed

univerkov | May 10, 2021 | education

The current in the circuit was doubled, and its resistance was halved. Has the circuit changed and how did the heat release?

I2 = 2 * I1.

R2 = R1 / 2.

Q2 / Q1 -?

The amount of thermal energy Q, which is released in the conductor through which the electric current flows, is determined by the Joule-Lenz law: Q = I ^ 2 * R * t, where I is the current in the conductor, t is the time of current passage through the conductor, R is the resistance conductor.

Q1 = I1 ^ 2 * R1 * t.

Q2 = I2 ^ 2 * R2 * t = (2 * I1) ^ 2 * R1 * t / 2 = 4 * I1 ^ 2 * R1 * t / 2 = 2 * I1 ^ 2 * R1 * t.

Q2 / Q1 = 2 * I1 ^ 2 * R1 * t / I1 ^ 2 * R1 * t = 2.

Answer: the amount of heat in the conductor will double: Q2 / Q1 = 2.

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