The current in the conductor increases uniformly by 8 A for 0.2 s. In this case, an EMF of self-induction of 0.2 V

The current in the conductor increases uniformly by 8 A for 0.2 s. In this case, an EMF of self-induction of 0.2 V appears in the conductor. What is the inductance of the conductor?

To calculate the required inductance of the taken conductor, we apply the formula: εi = L * ΔI / Δt and L = εi * Δt / ΔI.

Values of variables: εi – emerging EMF of self-induction (εi = 0.2 V); Δt – current rise time (Δt = 0.2 s); ΔI – increase in current strength (ΔI = 8 A).

Let’s calculate: L = εi * Δt / ΔI = 0.2 * 0.2 / 8 = 0.005 H = 5 mH.

Answer: 2) the inductance of the conductor is 5 mH.