The current in the electric lamp circuit is 0.3 A. How many electrons pass through the cross section of the spiral in 5 minutes?

Let’s translate all the values from given to the SI system:
t = 5min = 300 s
Current strength, a value that shows what electric charge passes through the cross section of the spiral in 1 s.
I = q / t, where q – electric charge, t – time.
Let us express the value of the charge from this expression:
q = I * t
Knowing the charge of one electron e = 1.6 * 10-19 C, we determine the number of electrons:
n = q / e
Let us substitute in this formula the expression for the charge passed through the thread:
n = q / e = I * t / e = 0.3 * 300 / 1.6 * 10-19 = 5.6 * 10 ^ 20
Answer: the number of electrons is 5.6 * 10 ^ 20.