The current on the spiral of the flashlight bulb is 0.2 amperes, the resistance of the spiral is 15 ohm.
| December 1, 2020 | education
The current on the spiral of the flashlight bulb is 0.2 amperes, the resistance of the spiral is 15 ohm. What kind of work does the current in a light bulb do in 2 minutes?
What about work)-?
I (current) = 0.2A
R (resistance) = 15Ω
t (time is converted into SI system) = 2min = 120s
A = I ^ 2 * R * t
A = 0.04A ^ 2 * 15Ω * 120s = 72J
Answer: 72 J
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