The current strength in a copper conductor with a cross section of 1.5 mm ^ 2 and a length of 14

The current strength in a copper conductor with a cross section of 1.5 mm ^ 2 and a length of 14 m is 2.2 A, determine the voltage at the ends of this conductor

Given:
According to the table, the resistivity of copper is – 0.017 Ohm × mm ^ 2 / m
S = 1.5mm ^ 2
l = 14m
J = 2.2A
First, we find the resistance of a given copper wire.
We transform the formula p = RS / l into R = pl / S
Where p is the resistivity of the conductor
S – cross section
l – wire length
Decision:
R = pl / S
R = 0.017 × 14 / 1.5 = 0.15 Ohm
Now we find the voltage according to Ohm’s law
U = RI
Substituting the values, we find.
U = 0.15 × 2.2 = 0.33V
Answer 0.33B