The current strength in an iron conductor with a length of 150 mm and a cross-sectional area of 0.02

The current strength in an iron conductor with a length of 150 mm and a cross-sectional area of 0.02 mm2 is 250 mA. what is the voltage at the ends of the conductor?

Data: I (current in the iron conductor) = 250 mA = 0.25 A; l (length) = 150 mm = 0.15 m; S (section) = 0.02 mm2; ρzh (specific electrical resistance of iron; t = 20 ºС) = 0.1 Ohm * mm2 / m.

The voltage at the ends of the specified iron conductor: U = R * I = ρzh * l / S * I = 0.1 * 0.15 / 0.02 * 0.25 = 0.1875 V.

Answer: The voltage is 0.1875 V.