The current through the resistor increases steadily from 5A to 15A in 10 seconds. what charge passed through the resistor during this time.
Task data: I1 (initial current in the resistor) = 5 A; I2 (end current) = 15 A; Δt (duration of current rise) = 10 s.
1) The current strength after 10 s is expressed by the formula t: I = I0 + k * t, whence, according to the conditions of the problem, k = (I – I0) / t = (15 – 5) / 10 = 1 and I = t.
2) Charge passed: q = 010∫ Idt = 010∫ tdt = t ^ 2/2 = 10 ^ 2/2 = 50 Cl.
Answer: In 10 seconds, a charge of 50 C passed through the resistor.
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