The cycle track has a curvature of 40 m. The cyclist moves along the cycle track at a speed of 10 m / s. Its centripetal acceleration is …

To calculate the magnitude of the centripetal acceleration of the presented cyclist on the rounding of the cycle track, we apply the formula: ac = Vw ^ 2 / R.
Variables: Vв – speed of the presented cyclist (Vв = 10 m / s); R – radius of curvature of the cycle track (R = 40 m).
Let’s perform the calculation: ac = Vw ^ 2 / R = 10 ^ 2/40 = 2.5 m / s2.
Answer: The centripetal acceleration of the presented cyclist is 2.5 m / s2.