The cyclic frequency of free electromagnetic oscillations in the oscillatory circuit is w = 1.0 * 10 to the 6th power of rad / s.

The cyclic frequency of free electromagnetic oscillations in the oscillatory circuit is w = 1.0 * 10 to the 6th power of rad / s. Determine the inductance of the coil if the capacitance of the capacitor is C = 25pF.

To determine the value of the inductance of the coil from the used oscillatory circuit, we use the formula: ω = 1 / √ (L * C); L * C = (1 / ω) ^ 2 and L = 1 / (ω ^ 2 * C).

Variables: ω – cyclic frequency of the arisen free oscillations (ω = 1 * 10 ^ 6 Hz); C is the capacitance of the circuit capacitor (C = 25 pF = 25 * 10 ^ -12 F).

Calculation: L = 1 / (ω2 * C) = 1 / ((1 * 10 ^ 6) 2 * 25 * 10 ^ -12) = 0.04 H = 40 mH.

Answer: The coil in the used oscillatory circuit has an inductance of 40 mH.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.