The cyclist at first covered 0.5 km for 10 km the next day he traveled in 12 minutes at a speed of 25 km / hour.
| December 23, 2020 | education
The cyclist at first covered 0.5 km for 10 km the next day he traveled in 12 minutes at a speed of 25 km / hour. And on the last 9 km of the road, he traveled with a speed of 18 km / h, the cyclist in the first half of the road needs to find an average speed.
First half of the journey
S / 2 = 24/2 = 12 (km.)
S ‘= 12-10 = 2 (km.) – part of the second path.
t ‘= 2/25 = 0.08 (h) – the time it takes for a cyclist to ride.
Vav2 = (S1 + S ‘) / (t1 + t’) = 12 / (0.5 + 0.08) = 20.68 approximately 20.7 = 21 (km / h)
Answer: 21 km / h
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