The cyclist descends the mountain with a constant acceleration of 0.8 m / s2. What is the speed

The cyclist descends the mountain with a constant acceleration of 0.8 m / s2. What is the speed of its movement in 10 s, if the initial was 2 m / s?

To solve this problem, first determine the difference between the initial and final speed.
For this we use the following formula:
a = V0 / t,
Where:
a – acceleration.
V0 is the difference between start and end speed.
t is the time of movement.
We express the value of the difference in speeds.
V0 = a * t = 0.8 * 10 = 8 m / s.
Find the final speed.
Since the original was 2 m / s, and the difference is 8 m / s, we get:
2 + 8 = 10 m / s.
Answer: After 10 seconds the speed of the cyclist was 10 m / s.



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