The cyclist descends the mountain with an acceleration of 0.5 m / s ².

The cyclist descends the mountain with an acceleration of 0.5 m / s ². What will be his speed in 30 seconds if the initial speed of the cyclist is 3 m / s?

Initial data: a (acceleration with which the cyclist descends the mountain) = 0.5 m / s2; t (time of movement of the cyclist) = 30 s; V0 (cyclist’s initial speed) = 3 m / s.

The cyclist’s speed after 30 seconds can be determined by the formula: V = V0 + a * t.

Let’s calculate: V = 3 + 0.5 * 30 = 18 m / s.

Answer: The speed of the cyclist after 30 seconds will be 18 m / s.