The cyclist drives down the hill, moving in a straight line and uniformly accelerated. During the descent

The cyclist drives down the hill, moving in a straight line and uniformly accelerated. During the descent, its speed increased by 13 m / s. Cyclist acceleration 0.25 m / s2. How long does the descent take?

To calculate the duration of the descent of the indicated cyclist, we use the formula: t = ΔV / a.

Variables: Δ V – increase in speed of the specified cyclist (V = 13 m / s); a – acceleration (a = 0.25 m / s2).

Let’s perform the calculation: t = ΔV / a = 13 / 0.25 = 52 s.

Answer:  the descent of the said cyclist lasted 52 seconds.