The cyclist left the city at a speed of 13.4 km / h. Two hours later, another cyclist rode out and after 4 hours

| February 14, 2021 | education

The cyclist left the city at a speed of 13.4 km / h. Two hours later, another cyclist rode out and after 4 hours caught up with the first cyclist. Find the speed of the second cyclist.

The first cyclist left 2 hours earlier than the second and rode in front for another 4 hours, until the second could catch up with him.

1) 2 + 4 = 6 (h) the first cyclist was riding until the second one caught up with him.

Knowing the speed and time, you can find the distance using the formula:

S = v * t, designations: S – distance, v – speed, t – time.

2) 13.4 * 6 = 80.4 (km) from the city, the cyclists are level.

The speed can be calculated using the formula:

v = S: t.

3) 80.4: 4 = 20.1 (km / h) speed of the 2nd cyclist.

Answer: the speed of the second is 20.1 km / h.



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