The cyclist moves at a constant speed V = 36 km / h in a circle with a radius of R = 34 m. What is a cyclist’s acceleration?

The cyclist moves at a constant speed V = 36 km / h in a circle with a radius of R = 34 m. What is a cyclist’s acceleration? What is the resulting force acting on him? Weight of a cyclist with a bicycle m = 80 kg

Let us express the speed in m / s:

V = 36 km / h = 36000/3600 = 10 m / s.

Centripetal acceleration:

acs = V ^ 2 / R = 10 ^ 2/34 = 2.94 m / s2.

Centripetal force:

Fcs = macs = 80 * 2.94 = 235 N.

Gravity:

Ft = mg = 80 * 9.8 = 784 N.

The centripetal force directed horizontally to the center of the circle is perpendicular to the vertical downward force of gravity. Hence the resulting force:

F = (Ftsc ^ 2 + Ft ^ 2) ^ 0.5 = (235 ^ 2 + 784 ^ 2) ^ 0.5 = 818 N.

Answer: 818 N.