The cyclist moves evenly around a circle with a radius of 100 m and makes 0.5 rpm

The cyclist moves evenly around a circle with a radius of 100 m and makes 0.5 rpm. Determine the path and movement of the cyclist in 60 s

R = 100 m.

v = 0.5 rpm.

t = 60 s.

S -?

L -?

The movement of the body S is a vector that connects its initial and final position of the cyclist when moving. During the time of movement t = 60 s, it will make a half turn and will be on the opposite side of the circle. Its movement S will be the diameter of the circle: S = 2 * R.

S = 2 * 100 m = 200 m.

The traversed path L is the length of the line that the body describes when moving. Since the body during the case t = 60 s the body will make a half turn, then its path will be half the circumference of a circle with a radius R: L = 2 * P * R / 2.

L = 2 * 3.14 * 100 m / 2 = 314 m.

Answer: the movement of the body is S = 200 m, the path of the body is L = 314 m.