The cyclist rides along the railroad. Two trains passed to meet him, one in t 6 minutes
| February 12, 2021 | education
The cyclist rides along the railroad. Two trains passed to meet him, one in t 6 minutes after the other at the same speed u-60 km / h. Find the cyclist’s speed (in km / h), knowing that the second ride left the station 8 minutes later than the first.
These problems: t (time between a cyclist meeting two trains) = 6 min; V1.2 (speed of each train) = 60 km / h; t1.2 (time difference between train exits from the station) = 8 min.
The cyclist’s speed can be expressed from the equality: V1.2 * t1.2 = S = (V1.2 + Vb) * t, whence V1.2 + Vb = V1.2 * t1.2 / t and Vb = V1.2 * t1.2 / t – V1.2.
Let’s calculate: Vв = 60 * 8/6 – 60 = 80 – 60 = 20 km / h.
Answer: The speed of this cyclist is 20 km / h.
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