The cyclist rode for half an hour at a speed of 24 km / h and then another hour at a speed of 18 km / h.

Initial data: t1 (the first time the cyclist moves) = 0.5 h; V1 (first speed) = 24 km / h; t2 (second time of movement) = 1 h; V2 (cyclist’s second speed) = 18 km / h.

The average speed of a cyclist is determined by the formula: Vav. = S / t = (S1 + S2) / (t1 + t2) = (V1 * t1 + V2 * t2) / (t1 + t2).

Calculation: Vav. = (24 * 0.5 + 18 * 1) / (0.5 + 1) = 30 / 1.5 = 20 km / h.

Answer: The cyclist traveled all the way at an average speed of 20 km / h.



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