The cyclist traveled 1200 m in 2 hours which way he will travel in 0.5 hours moving at the same speed.

Given: t1 (first time of movement of the cyclist in question) = 2 hours; S1 (first driven path) = 1200 m (1.2 km); t2 (second movement time) = 0.5 h; the speed of the cyclist in question is constant.

Since the speed of the cyclist under consideration is constant, we can express the distance traveled by him in 0.5 hours from this equality: S1 / t1 = V (const) = S2 / t2 and S2 = S1 * t2 / t1.

Calculation: S2 = 1.2 * 0.5 / 2 = 0.3 km or 300 m.

Answer: The cyclist will have to travel 300 meters.