The cyclist traveled half the way at a speed of 21 km / h, and the other half at a speed of 35 km / h

The cyclist traveled half the way at a speed of 21 km / h, and the other half at a speed of 35 km / h, spending an hour on the whole journey. How many meters did he drive during this time?

The solution of the problem:

1. The cyclist spent 3/7 hours for the entire journey, which means half of the time will be equal to:

3/7: 2 = 3/14 (hours);

2. Let’s calculate the distance that he traveled in the first part of the way at a speed of 21 km / h:

3/14 × 21 = 63/14 (km);

3. We also find out the second distance at a speed of 35 km / h:

3/14 × 35 = 105/14 (km);

4. Now, adding the obtained distances, we find out the general:

63/14 + 105/14 = 168/14 (km);

5. Reducing the fraction:

168/14 = 12 (km);

6. Since 1 km = 1000 m, we calculate the distance in meters:

12 × 1000 = 1 2000 (m)

Answer: the cyclist traveled 12,000 meters.