The cyclist will start two-down from the rest state and move in a linear, equally accelerated manner

The cyclist will start two-down from the rest state and move in a linear, equally accelerated manner. In 10 seconds after the start of movement, its speed becomes equal to 5 m / s. With what acceleration does the cyclist move?

To find the acceleration, we have everything, both the initial speed and the final speed. And the time it took the body to accelerate. Therefore, according to the formula a = V-Vo / t, now we just have to substitute the values.
a = 5-0 / 10 = 1/2 (m / c ^ 2)
Answer: a = 1/2 (m / c ^ 2)



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