The cylinder contained gas at a temperature of 273 K and a pressure of 1.2 * 10 Pa.

The cylinder contained gas at a temperature of 273 K and a pressure of 1.2 * 10 Pa. As a result of heating, the pressure increased to 1.8 * Pa. How many degrees is the gas heated?

It is known from the problem statement that the volume of gas in the cylinder remains constant, so its value can be neglected.

Since the volume of a gas is the ratio of its temperature to its pressure, in order to determine the new value of the gas temperature, it is necessary to divide the product of the initial temperature and the final pressure by the initial pressure.

In literal form, we get:

V = T / p.

V is the volume;

T is the temperature;

p is the pressure.

T1 / p1 = T2 / p2

T2 = (T1 * p2) / p1

We get:

T2 = (273 * 1.8 * 105) / 1.2 * 10 * 5 = 409.5 K.

This means the temperature has increased by:

409.5 – 273 = 136.5 K.

Answer:

The gas warmed up to 136.5 K.