The cylinder contains argon weighing 2 kg at a temperature of 20 degrees Celsius. What is the internal energy of the gas?

Initial data: m (mass of argon in the cylinder) = 2 kg; T (absolute temperature of argon) = 293 K (20 ºС).

Constants: i (the number of degrees of freedom of argon molecules (monatomic gas)) = 3; M (molar mass of argon) ≈ 40 g / mol (0.04 kg / mol); R (universal gas constant) = 8.31 J / (mol * K).

The internal energy of argon in the cylinder is determined by the formula: Q = 0.5 * i * (m / M) * R * ΔТ.

Calculation: Q = 0.5 * 3 * (2 / 0.04) * 8.31 * 293 ≈ 182.6 kJ.

Answer: The internal energy of argon is 182.6 kJ.



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