The cylinder contains nitrogen with a mass of m = 24 g at a temperature of T = 300 K. The gas is cooled

The cylinder contains nitrogen with a mass of m = 24 g at a temperature of T = 300 K. The gas is cooled isochorically so that its pressure drops n = 3 times. Then the gas is heated at constant pressure until its temperature reaches the initial one. Determine the work A done by the gas.

Let’s convert to the required units:
m = 24 g = 24 * 10 ^ -3 kg;
T1 = 300 K;
p1 = 3 * p2;
As we know, gas does work when heated, we write down the formula:
A = p * ΔV = m * R * ΔT / M;
ΔT = T1 – T2.
Then we substitute the values in the formula and calculate:
A = 24 * 10 ^ -3 * 8.31 * (300 – 100) / (28 * 10 ^ -3);
A = 1425 J.
Answer: A = 1425 J.