The daily human need for phosphorus is 1 g. The mass fractions of phosphorus in food (in percent) are known

The daily human need for phosphorus is 1 g. The mass fractions of phosphorus in food (in percent) are known: in meat – 0.204, in eggs – 0.224, in cheese – 0.701. Calculate the mass of each product, which contains the daily rate of phosphorus.

Given:
m (phosphorus) = 1 g
ω1 (phosphorus in meat) = 0.204%
ω2 (phosphorus in eggs) = 0.224%
ω3 (phosphorus in cheese) = 0.701%

To find:
m (meat) -?
m (eggs) -?
m (cheese) -?

Solution:
1) Calculate the mass of meat:
m (meat) = m (phosphorus) * 100% / ω1 (phosphorus) = 1 * 100% / 0.204% = 490.196 g;
2) Calculate the mass of eggs:
m (eggs) = m (phosphorus) * 100% / ω2 (phosphorus) = 1 * 100% / 0.224% = 446.429 g;
2) Calculate the mass of cheese:
m (cheese) = m (phosphorus) * 100% / ω3 (phosphorus) = 1 * 100% / 0.701% = 142.653 g.

Answer: The mass of meat is 490.196 g; eggs – 446.429 g; cheese – 142.653 g.