The data transfer rate over a certain communication channel is 32 Kbps. The transfer of a text file via

The data transfer rate over a certain communication channel is 32 Kbps. The transfer of a text file via this communication channel took 15 seconds. Determine how many pages the transferred text contained if it is known that the information weight of one character is 8 bytes, and on one page there are 48 characters.

Let’s find the information volume of this file.

I = v * t = 32 kbps * 15 s = 480 kbps = 480 * 1000 bits = 480,000 bits.

Now let’s determine the number of pages in the transferred text.

n = I / (8 bytes * 48) = 480,000 bits / (8 * 8 bits * 48) = 10,000 / 64 = 156.25 pages.

Answer: this text contained 156.25 pages.