The data transfer rate through the analog modem is 128,000 bps. A file of 375 kilobytes is transferred

The data transfer rate through the analog modem is 128,000 bps. A file of 375 kilobytes is transferred through this connection. Determine the file transfer time in seconds.

1. Let’s translate the connection speed of 128000 bps to kilobytes per second.

1 byte = 8 bits means 128000 bits = 128000/8 = 16000 bytes

1 kilobyte = 1024 bytes means 16000 bytes = 16000/1024 = 15.625 kilobytes.

We got that the connection speed is 15.625 kb / s

2. Determine the transfer time of a 375 kilobyte file:

375 / 15.625 = 24 sec.

Answer: 24 seconds.



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