The decomposition of an ammonium halide weighing 4.9 g yielded ammonia with a volume of 1.12 l

The decomposition of an ammonium halide weighing 4.9 g yielded ammonia with a volume of 1.12 l (the volume was brought to normal conditions). What kind of halide was taken?

Let’s calculate the chemical amount of ammonia.

For this purpose, we divide the amount of substance by the standard volume of 1 mole of gas (filling 22.40 liters):

N NH3 = 1.12 / 22.4 = 0.05 mol;

Let’s find the molar mass of the salt:

M 4.9 / 0.05 = 98 grams / mol;

This salt is ammonium bromide.

M NH4Br = 14 + 4 + 80 = 98 grams / mol;