The decomposition of Berthollet’s salt is expressed by the equation KClO (3) = 2KCl + 3O2.

The decomposition of Berthollet’s salt is expressed by the equation KClO (3) = 2KCl + 3O2. How many liters of oxygen are released during the decomposition of 8 mol of berthollet’s salt?

Given:

n (KClO3) = 8 mol

To find:

V (O2) -?

Decision:

We focus on the reaction equation: KClO3 = 2KCl + 3O2.

1) We compose a logical expression:

If 1 mole of berthollet’s salt gives 3 moles of oxygen,

then 8 moles of berthollet’s salt will give x moles of oxygen,

then x = 8 mol * 3 mol: 1 mol = 24 mol of oxygen.

2) n = V: Vm

Vm = 22.4 l / mol

If 1 mole of gas occupies a volume of 22.4 liters, then 24 moles of gas occupy:

24 mol * 22.4 l / mol = 537.6 liters.

Answer: When 8 mol of berthollet’s salt decomposes, 537.6 liters of oxygen will be released.