The decomposition of magnesium carbonate weighing 33.6 g yielded 7.2 liters of carbon dioxide.

The decomposition of magnesium carbonate weighing 33.6 g yielded 7.2 liters of carbon dioxide. Determine the reaction yield as a percentage.

Let’s implement the solution:

In accordance with the condition of the problem, we write the data:
MgCO3 = MgO + CO2 – decomposition, carbon dioxide is released;

Calculations by the formulas of substances:
M (MgCO3) = 84.3 g / mol;

M (CO2) = 44 g / mol;

Y (MgCO3) = m / M = 33.6 / 84.3 = 0.4 mol;

Y (CO2) = 0.4 mol since the amount of substances is 1 mol.

We find the volume and yield of the product:
V (CO2) = 0.4 * 22.4 = 8.86 L;

W = 7.2 / 8.96 * 100 = 80.36%

Answer: the yield of carbon monoxide (4) was 80.36%