The degree measure of the acute angle of a rectangular trapezoid is 45 degrees, and the height drawn

The degree measure of the acute angle of a rectangular trapezoid is 45 degrees, and the height drawn from the top of the obtuse angle divides the trapezoid into a triangle and a square whose area is 36 cm square. Calculate the area of the trapezoid.

Since ABCH is a square, and its area is 36 cm2, the length of its side is equal to the square root of the area.

AB = BC = CH = AH = √36 = 6 cm.

In a right-angled triangle CDH, one of the acute angles is 45, then the triangle is isosceles, DH = CH = 6 cm.

Determine the length of the larger base of the trapezoid.

AD = AH + DH = 6 + 6 = 12 cm.

Determine the area of the trapezoid.

Savsd = (ВС + АD) * СН / 2 = (6 + 12) * 6/2 = 54 cm2.

Answer: The area of the trapezoid is 54 cm2.



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