The diagonal AC of the trapezoid ABCD is the bisector of the acute angle DAB

The diagonal AC of the trapezoid ABCD is the bisector of the acute angle DAB. Determine the degree measure of the BAC angle if the ABC angle is 110 degrees.

By the property of the angles of the trapezoid, the sum of the angles at its lateral side is 180, then the angle ABD = (180 – ABC) = (180 – 110) = 70.

Since AC is the bisector of the BAD angle, the angle BAC = CAD = 70/2 = 35.

Answer: The value of the angle BAC is 35.



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