The diagonal BD of parallelogram ABCD makes angles of 65 ° and 50 ° with its sides.

The diagonal BD of parallelogram ABCD makes angles of 65 ° and 50 ° with its sides. Find the smaller angle of the parallelogram.

To solve it, draw a parallelogram ABCD, in which we draw a diagonal AC.

So, according to the condition, the diagonal of the larger angle turns out to form angles with its sides equal to 50 ° and 65 °, then this whole angle is equal to 65 + 50 = 115 °.

Since the lesser and greater angles of the parallelogram are equal to 180 ° in total, the lesser angle is equal to: 180 – 115 = 65 °.



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