The diagonal of a cube is 12 cm, find the surface area of a cube.

From a right-angled triangle, in which the hypotenuse is the diagonal of the cube D = 12, one leg is the height of the cube a, the second leg is the diagonal of the base of the cube d = a√2, according to the Pythagoras rule we find D:
D2 = a2 + d2 = a2 + 2a2 = 3a2
Side of the cube a2 = D2 / 3 = 144/3 = 48
Area S total = 6a2 = 6 * 48 = 288



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