The diagonal of rectangle ABCD intersects at point O. The ABO angle is 36 degrees. Find Angle AOD

Consider a triangle ABD. Angle ABD is 36, angle BAD is 90. Find Angle BDA: 180-90-36 = 54.
Consider the triangle AOD. It is isosceles, since the diagonals are halved by the intersection point. Therefore, the angles at the base are: Angle OAD = Angle ODA = 54. Two angles are known, find the third angle AOD: 180-54-54 = 72
ANSWER: AOD angle = 72